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8b^2-13b+6=5b^2
We move all terms to the left:
8b^2-13b+6-(5b^2)=0
determiningTheFunctionDomain 8b^2-5b^2-13b+6=0
We add all the numbers together, and all the variables
3b^2-13b+6=0
a = 3; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·3·6
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{97}}{2*3}=\frac{13-\sqrt{97}}{6} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{97}}{2*3}=\frac{13+\sqrt{97}}{6} $
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